fmod, fmodl

raw OCR

Calculates x modulo y, the remainder of x/y.

Defined in header <math.h>

Syntax

#include <math.h>
double fmod(double  x, double y);
long double fmodl(long double x, long double y);

Portability

	DOS	UNIX	Windows	ANSI C	C++ only
fmod	■	■	■	■
fmodI	■		■

Remarks

fmod calculates x modulo y (the remainder /, where x = ay + fior some integer a and 0 < / < y). fmod I is the long double version; it takes long double arguments and returns a long double result.

Return value

fmod and fmodi return the remainder /, where x = ay + f{as described). Where y = 0, fmod and fmod I return 0.

Example

#include <stdio.h>
#include <math.h>

int main (void)
{
   double X = 5.0, y = 2.0;
   double result;
   result = fmod(x,y);
   printf("The remainder of  (%lf / %lf) is %lf\n", x, y, result);
   return 0;

Program   output

The remainder of 5.0 / 2.0 is 1.0.

Differences from modern implementations

Nothing recorded yet.

Modern references

These are search links, not yet checked by hand.

Extraction notes

heading `f mod, f modi` read as `fmod, fmodl`

Stable link: /3.1/math.h/fmod/ · short form /3.1/fmod/